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-5/6h-2/3h=-24
We move all terms to the left:
-5/6h-2/3h-(-24)=0
Domain of the equation: 6h!=0
h!=0/6
h!=0
h∈R
Domain of the equation: 3h!=0We add all the numbers together, and all the variables
h!=0/3
h!=0
h∈R
-5/6h-2/3h+24=0
We calculate fractions
(-15h)/18h^2+(-12h)/18h^2+24=0
We multiply all the terms by the denominator
(-15h)+(-12h)+24*18h^2=0
Wy multiply elements
432h^2+(-15h)+(-12h)=0
We get rid of parentheses
432h^2-15h-12h=0
We add all the numbers together, and all the variables
432h^2-27h=0
a = 432; b = -27; c = 0;
Δ = b2-4ac
Δ = -272-4·432·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-27}{2*432}=\frac{0}{864} =0 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+27}{2*432}=\frac{54}{864} =1/16 $
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