3(k-9)=2(4k-1)

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Solution for 3(k-9)=2(4k-1) equation: 



3(k-9)=2(4k-1)

We move all terms to the left:

3(k-9)-(2(4k-1))=0

We multiply parentheses

3k-(2(4k-1))-27=0



We calculate terms in parentheses: -(2(4k-1)), so:

2(4k-1)

We multiply parentheses

8k-2

Back to the equation:

-(8k-2)



We get rid of parentheses

3k-8k+2-27=0

We add all the numbers together, and all the variables

-5k-25=0

We move all terms containing k to the left, all other terms to the right

-5k=25

k=25/-5

k=-5

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