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-0.33x^2=x-6
We move all terms to the left:
-0.33x^2-(x-6)=0
We get rid of parentheses
-0.33x^2-x+6=0
We add all the numbers together, and all the variables
-0.33x^2-1x+6=0
a = -0.33; b = -1; c = +6;
Δ = b2-4ac
Δ = -12-4·(-0.33)·6
Δ = 8.92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{8.92}}{2*-0.33}=\frac{1-\sqrt{8.92}}{-0.66} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{8.92}}{2*-0.33}=\frac{1+\sqrt{8.92}}{-0.66} $
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