3(b+2)=1

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Solution for 3(b+2)=1 equation: 



3(b+2)=1

We move all terms to the left:

3(b+2)-(1)=0

We multiply parentheses

3b+6-1=0

We add all the numbers together, and all the variables

3b+5=0

We move all terms containing b to the left, all other terms to the right

3b=-5

b=-5/3

b=-1+2/3

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