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3(k+1)+5k=-1+5(k-1)
We move all terms to the left:
3(k+1)+5k-(-1+5(k-1))=0
We add all the numbers together, and all the variables
5k+3(k+1)-(-1+5(k-1))=0
We multiply parentheses
5k+3k-(-1+5(k-1))+3=0
We calculate terms in parentheses: -(-1+5(k-1)), so:We add all the numbers together, and all the variables
-1+5(k-1)
determiningTheFunctionDomain 5(k-1)-1
We multiply parentheses
5k-5-1
We add all the numbers together, and all the variables
5k-6
Back to the equation:
-(5k-6)
8k-(5k-6)+3=0
We get rid of parentheses
8k-5k+6+3=0
We add all the numbers together, and all the variables
3k+9=0
We move all terms containing k to the left, all other terms to the right
3k=-9
k=-9/3
k=-3
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