6(z+2)-2(2z+5=18

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Solution for 6(z+2)-2(2z+5=18 equation: 



6(z+2)-2(2z+5=18

We move all terms to the left:

6(z+2)-2(2z+5-(18)=0

We multiply parentheses

6z-2(2z+5-18+12=0

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