6(x-2+3x)=-3(-4x+2-5)

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Solution for 6(x-2+3x)=-3(-4x+2-5) equation: 



6(x-2+3x)=-3(-4x+2-5)

We move all terms to the left:

6(x-2+3x)-(-3(-4x+2-5))=0

We add all the numbers together, and all the variables

6(4x-2)-(-3(-4x-3))=0

We multiply parentheses

24x-(-3(-4x-3))-12=0



We calculate terms in parentheses: -(-3(-4x-3)), so:

-3(-4x-3)

We multiply parentheses

12x+9

Back to the equation:

-(12x+9)



We get rid of parentheses

24x-12x-9-12=0

We add all the numbers together, and all the variables

12x-21=0

We move all terms containing x to the left, all other terms to the right

12x=21

x=21/12

x=1+3/4

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