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3(3y+3)=2(2y+4)
We move all terms to the left:
3(3y+3)-(2(2y+4))=0
We multiply parentheses
9y-(2(2y+4))+9=0
We calculate terms in parentheses: -(2(2y+4)), so:We get rid of parentheses
2(2y+4)
We multiply parentheses
4y+8
Back to the equation:
-(4y+8)
9y-4y-8+9=0
We add all the numbers together, and all the variables
5y+1=0
We move all terms containing y to the left, all other terms to the right
5y=-1
y=-1/5
y=-1/5
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