2y2+11y+10=0

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Solution for 2y2+11y+10=0 equation: 



2y^2+11y+10=0

a = 2; b = 11; c = +10;
Δ = b2-4ac
Δ = 112-4·2·10
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{41}}{2*2}=\frac{-11-\sqrt{41}}{4}
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{41}}{2*2}=\frac{-11+\sqrt{41}}{4}
$

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