3(j+4)+2=20

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Solution for 3(j+4)+2=20 equation: 



3(j+4)+2=20

We move all terms to the left:

3(j+4)+2-(20)=0

We add all the numbers together, and all the variables

3(j+4)-18=0

We multiply parentheses

3j+12-18=0

We add all the numbers together, and all the variables

3j-6=0

We move all terms containing j to the left, all other terms to the right

3j=6

j=6/3

j=2

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