y+5(y-4)-20=2(-6+4y)

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Solution for y+5(y-4)-20=2(-6+4y) equation: 



y+5(y-4)-20=2(-6+4y)

We move all terms to the left:

y+5(y-4)-20-(2(-6+4y))=0

We add all the numbers together, and all the variables

y+5(y-4)-(2(4y-6))-20=0

We multiply parentheses

y+5y-(2(4y-6))-20-20=0



We calculate terms in parentheses: -(2(4y-6)), so:

2(4y-6)

We multiply parentheses

8y-12

Back to the equation:

-(8y-12)



We add all the numbers together, and all the variables

6y-(8y-12)-40=0

We get rid of parentheses

6y-8y+12-40=0

We add all the numbers together, and all the variables

-2y-28=0

We move all terms containing y to the left, all other terms to the right

-2y=28

y=28/-2

y=-14

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