450=25x2+50x

Solution for 450=25x2+50x equation:

450=25x^2+50x

We move all terms to the left:

450-(25x^2+50x)=0

We get rid of parentheses

-25x^2-50x+450=0

a = -25; b = -50; c = +450;
Δ = b2-4ac
Δ = -502-4·(-25)·450
Δ = 47500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{47500}=\sqrt{2500*19}=\sqrt{2500}*\sqrt{19}=50\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-50\sqrt{19}}{2*-25}=\frac{50-50\sqrt{19}}{-50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+50\sqrt{19}}{2*-25}=\frac{50+50\sqrt{19}}{-50}
$