3(j+4)+-2=j

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Solution for 3(j+4)+-2=j equation: 



3(j+4)+-2=j

We move all terms to the left:

3(j+4)+-2-(j)=0

We add all the numbers together, and all the variables

-1j+3(j+4)=0

We multiply parentheses

-1j+3j+12=0

We add all the numbers together, and all the variables

2j+12=0

We move all terms containing j to the left, all other terms to the right

2j=-12

j=-12/2

j=-6

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