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2y-2=4y-6/2y
We move all terms to the left:
2y-2-(4y-6/2y)=0
Domain of the equation: 2y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
2y-(+4y-6/2y)-2=0
We get rid of parentheses
2y-4y+6/2y-2=0
We multiply all the terms by the denominator
2y*2y-4y*2y-2*2y+6=0
Wy multiply elements
4y^2-8y^2-4y+6=0
We add all the numbers together, and all the variables
-4y^2-4y+6=0
a = -4; b = -4; c = +6;
Δ = b2-4ac
Δ = -42-4·(-4)·6
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{7}}{2*-4}=\frac{4-4\sqrt{7}}{-8} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{7}}{2*-4}=\frac{4+4\sqrt{7}}{-8} $
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