6(4y-2)=(5+3y)

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Solution for 6(4y-2)=(5+3y) equation: 



6(4y-2)=(5+3y)

We move all terms to the left:

6(4y-2)-((5+3y))=0

We add all the numbers together, and all the variables

6(4y-2)-((3y+5))=0

We multiply parentheses

24y-((3y+5))-12=0



We calculate terms in parentheses: -((3y+5)), so:

(3y+5)

We get rid of parentheses

3y+5

Back to the equation:

-(3y+5)



We get rid of parentheses

24y-3y-5-12=0

We add all the numbers together, and all the variables

21y-17=0

We move all terms containing y to the left, all other terms to the right

21y=17

y=17/21

y=17/21

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