3(d+1)=4(d-2)

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Solution for 3(d+1)=4(d-2) equation: 



3(d+1)=4(d-2)

We move all terms to the left:

3(d+1)-(4(d-2))=0

We multiply parentheses

3d-(4(d-2))+3=0



We calculate terms in parentheses: -(4(d-2)), so:

4(d-2)

We multiply parentheses

4d-8

Back to the equation:

-(4d-8)



We get rid of parentheses

3d-4d+8+3=0

We add all the numbers together, and all the variables

-1d+11=0

We move all terms containing d to the left, all other terms to the right

-d=-11

d=-11/-1

d=+11

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