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2(4x+20)=3(x+15)
We move all terms to the left:
2(4x+20)-(3(x+15))=0
We multiply parentheses
8x-(3(x+15))+40=0
We calculate terms in parentheses: -(3(x+15)), so:We get rid of parentheses
3(x+15)
We multiply parentheses
3x+45
Back to the equation:
-(3x+45)
8x-3x-45+40=0
We add all the numbers together, and all the variables
5x-5=0
We move all terms containing x to the left, all other terms to the right
5x=5
x=5/5
x=1
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