5(2t-4)=3(7t-2)-8

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Solution for 5(2t-4)=3(7t-2)-8 equation: 



5(2t-4)=3(7t-2)-8

We move all terms to the left:

5(2t-4)-(3(7t-2)-8)=0

We multiply parentheses

10t-(3(7t-2)-8)-20=0



We calculate terms in parentheses: -(3(7t-2)-8), so:

3(7t-2)-8

We multiply parentheses

21t-6-8

We add all the numbers together, and all the variables

21t-14

Back to the equation:

-(21t-14)



We get rid of parentheses

10t-21t+14-20=0

We add all the numbers together, and all the variables

-11t-6=0

We move all terms containing t to the left, all other terms to the right

-11t=6

t=6/-11

t=-6/11

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