5(2t-4)=3(7t-2)

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Solution for 5(2t-4)=3(7t-2) equation: 



5(2t-4)=3(7t-2)

We move all terms to the left:

5(2t-4)-(3(7t-2))=0

We multiply parentheses

10t-(3(7t-2))-20=0



We calculate terms in parentheses: -(3(7t-2)), so:

3(7t-2)

We multiply parentheses

21t-6

Back to the equation:

-(21t-6)



We get rid of parentheses

10t-21t+6-20=0

We add all the numbers together, and all the variables

-11t-14=0

We move all terms containing t to the left, all other terms to the right

-11t=14

t=14/-11

t=-1+3/11

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