3(c-6)+1=10

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Solution for 3(c-6)+1=10 equation:



3(c-6)+1=10
We move all terms to the left:
3(c-6)+1-(10)=0
We add all the numbers together, and all the variables
3(c-6)-9=0
We multiply parentheses
3c-18-9=0
We add all the numbers together, and all the variables
3c-27=0
We move all terms containing c to the left, all other terms to the right
3c=27
c=27/3
c=9

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