-5a(4a-7)=-6a-35

Solution for -5a(4a-7)=-6a-35 equation:

-5a(4a-7)=-6a-35

We move all terms to the left:

-5a(4a-7)-(-6a-35)=0

We multiply parentheses

-20a^2+35a-(-6a-35)=0

We get rid of parentheses

-20a^2+35a+6a+35=0

We add all the numbers together, and all the variables

-20a^2+41a+35=0

a = -20; b = 41; c = +35;
Δ = b2-4ac
Δ = 412-4·(-20)·35
Δ = 4481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-\sqrt{4481}}{2*-20}=\frac{-41-\sqrt{4481}}{-40}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+\sqrt{4481}}{2*-20}=\frac{-41+\sqrt{4481}}{-40}
$