1/3(3-6t)=1/2(-8t+14)

Solution for 1/3(3-6t)=1/2(-8t+14) equation:

1/3(3-6t)=1/2(-8t+14)

We move all terms to the left:

1/3(3-6t)-(1/2(-8t+14))=0


Domain of the equation: 3(3-6t)!=0

t∈R



Domain of the equation: 2(-8t+14))!=0

t∈R


We add all the numbers together, and all the variables

1/3(-6t+3)-(1/2(-8t+14))=0

We calculate fractions


(2t(-)/(3(-6t+3)*2(-8t+14)))+(-3t0/(3(-6t+3)*2(-8t+14)))=0


We calculate terms in parentheses: +(2t(-)/(3(-6t+3)*2(-8t+14))), so:

2t(-)/(3(-6t+3)*2(-8t+14))

We add all the numbers together, and all the variables

2t0/(3(-6t+3)*2(-8t+14))

We multiply all the terms by the denominator


2t0

We add all the numbers together, and all the variables

2t

Back to the equation:

+(2t)



We calculate terms in parentheses: +(-3t0/(3(-6t+3)*2(-8t+14))), so:

-3t0/(3(-6t+3)*2(-8t+14))

We multiply all the terms by the denominator


-3t0

We add all the numbers together, and all the variables

-3t

Back to the equation:

+(-3t)


We get rid of parentheses

2t-3t=0

We add all the numbers together, and all the variables

-t=0

t=0/-1

t=0