-4(x+)3-3x=2(x+3)

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Solution for -4(x+)3-3x=2(x+3) equation: 



-4(x+)3-3x=2(x+3)

We move all terms to the left:

-4(x+)3-3x-(2(x+3))=0

We add all the numbers together, and all the variables

-4(+x)3-3x-(2(x+3))=0

We add all the numbers together, and all the variables

-3x-4(+x)3-(2(x+3))=0

We multiply parentheses

-3x-12x-(2(x+3))=0



We calculate terms in parentheses: -(2(x+3)), so:

2(x+3)

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

-15x-(2x+6)=0

We get rid of parentheses

-15x-2x-6=0

We add all the numbers together, and all the variables

-17x-6=0

We move all terms containing x to the left, all other terms to the right

-17x=6

x=6/-17

x=-6/17

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