3(c-4)=9(c+2)

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Solution for 3(c-4)=9(c+2) equation: 



3(c-4)=9(c+2)

We move all terms to the left:

3(c-4)-(9(c+2))=0

We multiply parentheses

3c-(9(c+2))-12=0



We calculate terms in parentheses: -(9(c+2)), so:

9(c+2)

We multiply parentheses

9c+18

Back to the equation:

-(9c+18)



We get rid of parentheses

3c-9c-18-12=0

We add all the numbers together, and all the variables

-6c-30=0

We move all terms containing c to the left, all other terms to the right

-6c=30

c=30/-6

c=-5

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