x=(2x+3x)+62

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Solution for x=(2x+3x)+62 equation: 



x=(2x+3x)+62

We move all terms to the left:

x-((2x+3x)+62)=0

We add all the numbers together, and all the variables

x-((+5x)+62)=0



We calculate terms in parentheses: -((+5x)+62), so:

(+5x)+62

We get rid of parentheses

5x+62

Back to the equation:

-(5x+62)



We get rid of parentheses

x-5x-62=0

We add all the numbers together, and all the variables

-4x-62=0

We move all terms containing x to the left, all other terms to the right

-4x=62

x=62/-4

x=-15+1/2

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