3(x+12)=7(x+4)

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Solution for 3(x+12)=7(x+4) equation: 



3(x+12)=7(x+4)

We move all terms to the left:

3(x+12)-(7(x+4))=0

We multiply parentheses

3x-(7(x+4))+36=0



We calculate terms in parentheses: -(7(x+4)), so:

7(x+4)

We multiply parentheses

7x+28

Back to the equation:

-(7x+28)



We get rid of parentheses

3x-7x-28+36=0

We add all the numbers together, and all the variables

-4x+8=0

We move all terms containing x to the left, all other terms to the right

-4x=-8

x=-8/-4

x=+2

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