4(t-7)=3(2t+3)

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Solution for 4(t-7)=3(2t+3) equation: 



4(t-7)=3(2t+3)

We move all terms to the left:

4(t-7)-(3(2t+3))=0

We multiply parentheses

4t-(3(2t+3))-28=0



We calculate terms in parentheses: -(3(2t+3)), so:

3(2t+3)

We multiply parentheses

6t+9

Back to the equation:

-(6t+9)



We get rid of parentheses

4t-6t-9-28=0

We add all the numbers together, and all the variables

-2t-37=0

We move all terms containing t to the left, all other terms to the right

-2t=37

t=37/-2

t=-18+1/2

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