3(b-4)+5=b

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Solution for 3(b-4)+5=b equation: 



3(b-4)+5=b

We move all terms to the left:

3(b-4)+5-(b)=0

We add all the numbers together, and all the variables

-1b+3(b-4)+5=0

We multiply parentheses

-1b+3b-12+5=0

We add all the numbers together, and all the variables

2b-7=0

We move all terms containing b to the left, all other terms to the right

2b=7

b=7/2

b=3+1/2

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