3(b-4)=+5b

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Solution for 3(b-4)=+5b equation: 



3(b-4)=+5b

We move all terms to the left:

3(b-4)-(+5b)=0

We multiply parentheses

3b-(+5b)-12=0

We get rid of parentheses

3b-5b-12=0

We add all the numbers together, and all the variables

-2b-12=0

We move all terms containing b to the left, all other terms to the right

-2b=12

b=12/-2

b=-6

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