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1/2x+2/3x+5=1/3
We move all terms to the left:
1/2x+2/3x+5-(1/3)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
1/2x+2/3x+5-(+1/3)=0
We get rid of parentheses
1/2x+2/3x+5-1/3=0
We calculate fractions
27x/54x^2+4x/54x^2+(-2x)/54x^2+5=0
We multiply all the terms by the denominator
27x+4x+(-2x)+5*54x^2=0
We add all the numbers together, and all the variables
31x+(-2x)+5*54x^2=0
Wy multiply elements
270x^2+31x+(-2x)=0
We get rid of parentheses
270x^2+31x-2x=0
We add all the numbers together, and all the variables
270x^2+29x=0
a = 270; b = 29; c = 0;
Δ = b2-4ac
Δ = 292-4·270·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-29}{2*270}=\frac{-58}{540} =-29/270 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+29}{2*270}=\frac{0}{540} =0 $
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