3(b-15)+2b=120

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Solution for 3(b-15)+2b=120 equation: 



3(b-15)+2b=120

We move all terms to the left:

3(b-15)+2b-(120)=0

We add all the numbers together, and all the variables

2b+3(b-15)-120=0

We multiply parentheses

2b+3b-45-120=0

We add all the numbers together, and all the variables

5b-165=0

We move all terms containing b to the left, all other terms to the right

5b=165

b=165/5

b=33

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