8(u+8)8u=8

Solution for 8(u+8)8u=8 equation:

8(u+8)8u=8

We move all terms to the left:

8(u+8)8u-(8)=0

We multiply parentheses

64u^2+512u-8=0

a = 64; b = 512; c = -8;
Δ = b2-4ac
Δ = 5122-4·64·(-8)
Δ = 264192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{264192}=\sqrt{1024*258}=\sqrt{1024}*\sqrt{258}=32\sqrt{258}$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(512)-32\sqrt{258}}{2*64}=\frac{-512-32\sqrt{258}}{128}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(512)+32\sqrt{258}}{2*64}=\frac{-512+32\sqrt{258}}{128}
$