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(5x-7)(5x+1)=0
We multiply parentheses ..
(+25x^2+5x-35x-7)=0
We get rid of parentheses
25x^2+5x-35x-7=0
We add all the numbers together, and all the variables
25x^2-30x-7=0
a = 25; b = -30; c = -7;
Δ = b2-4ac
Δ = -302-4·25·(-7)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-40}{2*25}=\frac{-10}{50} =-1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+40}{2*25}=\frac{70}{50} =1+2/5 $
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