3(b+7)=6(b-7)

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Solution for 3(b+7)=6(b-7) equation: 



3(b+7)=6(b-7)

We move all terms to the left:

3(b+7)-(6(b-7))=0

We multiply parentheses

3b-(6(b-7))+21=0



We calculate terms in parentheses: -(6(b-7)), so:

6(b-7)

We multiply parentheses

6b-42

Back to the equation:

-(6b-42)



We get rid of parentheses

3b-6b+42+21=0

We add all the numbers together, and all the variables

-3b+63=0

We move all terms containing b to the left, all other terms to the right

-3b=-63

b=-63/-3

b=+21

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