-2x-3-3(3x-5)=-6x+(-2+6x-4)

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Solution for -2x-3-3(3x-5)=-6x+(-2+6x-4) equation: 



-2x-3-3(3x-5)=-6x+(-2+6x-4)

We move all terms to the left:

-2x-3-3(3x-5)-(-6x+(-2+6x-4))=0

We add all the numbers together, and all the variables

-2x-3(3x-5)-(-6x+(6x-6))-3=0

We multiply parentheses

-2x-9x-(-6x+(6x-6))+15-3=0



We calculate terms in parentheses: -(-6x+(6x-6)), so:

-6x+(6x-6)

We get rid of parentheses

-6x+6x-6

We add all the numbers together, and all the variables

-6

Back to the equation:

-(-6)



We add all the numbers together, and all the variables

-11x+18=0

We move all terms containing x to the left, all other terms to the right

-11x=-18

x=-18/-11

x=1+7/11

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