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57/60x+9=x
We move all terms to the left:
57/60x+9-(x)=0
Domain of the equation: 60x!=0We add all the numbers together, and all the variables
x!=0/60
x!=0
x∈R
-1x+57/60x+9=0
We multiply all the terms by the denominator
-1x*60x+9*60x+57=0
Wy multiply elements
-60x^2+540x+57=0
a = -60; b = 540; c = +57;
Δ = b2-4ac
Δ = 5402-4·(-60)·57
Δ = 305280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{305280}=\sqrt{576*530}=\sqrt{576}*\sqrt{530}=24\sqrt{530}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(540)-24\sqrt{530}}{2*-60}=\frac{-540-24\sqrt{530}}{-120} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(540)+24\sqrt{530}}{2*-60}=\frac{-540+24\sqrt{530}}{-120} $
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