3(b+4)=5(b+1)-7b

Solution for 3(b+4)=5(b+1)-7b equation:

3(b+4)=5(b+1)-7b

We move all terms to the left:

3(b+4)-(5(b+1)-7b)=0

We multiply parentheses

3b-(5(b+1)-7b)+12=0


We calculate terms in parentheses: -(5(b+1)-7b), so:

5(b+1)-7b

We add all the numbers together, and all the variables

-7b+5(b+1)

We multiply parentheses

-7b+5b+5

We add all the numbers together, and all the variables

-2b+5

Back to the equation:

-(-2b+5)


We get rid of parentheses

3b+2b-5+12=0

We add all the numbers together, and all the variables

5b+7=0

We move all terms containing b to the left, all other terms to the right

5b=-7

b=-7/5

b=-1+2/5