x+4=2(x-1)+13

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Solution for x+4=2(x-1)+13 equation: 



x+4=2(x-1)+13

We move all terms to the left:

x+4-(2(x-1)+13)=0



We calculate terms in parentheses: -(2(x-1)+13), so:

2(x-1)+13

We multiply parentheses

2x-2+13

We add all the numbers together, and all the variables

2x+11

Back to the equation:

-(2x+11)



We get rid of parentheses

x-2x-11+4=0

We add all the numbers together, and all the variables

-1x-7=0

We move all terms containing x to the left, all other terms to the right

-x=7

x=7/-1

x=-7

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