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5(2c+7)-3=(c+5)
We move all terms to the left:
5(2c+7)-3-((c+5))=0
We multiply parentheses
10c-((c+5))+35-3=0
We calculate terms in parentheses: -((c+5)), so:We add all the numbers together, and all the variables
(c+5)
We get rid of parentheses
c+5
Back to the equation:
-(c+5)
10c-(c+5)+32=0
We get rid of parentheses
10c-c-5+32=0
We add all the numbers together, and all the variables
9c+27=0
We move all terms containing c to the left, all other terms to the right
9c=-27
c=-27/9
c=-3
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