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3(b*b)+6b+3=0
We add all the numbers together, and all the variables
3(+b*b)+6b+3=0
We add all the numbers together, and all the variables
6b+3(+b*b)+3=0
We multiply parentheses
3b^2+6b+3=0
a = 3; b = 6; c = +3;
Δ = b2-4ac
Δ = 62-4·3·3
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$b=\frac{-b}{2a}=\frac{-6}{6}=-1$
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