24/c-3=1,c=

Solution for 24/c-3=1,c= equation:

24/c-3=1.c=

We move all terms to the left:

24/c-3-(1.c)=0


Domain of the equation: c!=0

c∈R


We add all the numbers together, and all the variables

24/c-(+c)-3=0

We get rid of parentheses

24/c-c-3=0

We multiply all the terms by the denominator


-c*c-3*c+24=0

We add all the numbers together, and all the variables

-3c-c*c+24=0

Wy multiply elements

-1c^2-3c+24=0

a = -1; b = -3; c = +24;
Δ = b2-4ac
Δ = -32-4·(-1)·24
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{105}}{2*-1}=\frac{3-\sqrt{105}}{-2}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{105}}{2*-1}=\frac{3+\sqrt{105}}{-2}
$