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3(a+1)=(2a+5)
We move all terms to the left:
3(a+1)-((2a+5))=0
We multiply parentheses
3a-((2a+5))+3=0
We calculate terms in parentheses: -((2a+5)), so:We get rid of parentheses
(2a+5)
We get rid of parentheses
2a+5
Back to the equation:
-(2a+5)
3a-2a-5+3=0
We add all the numbers together, and all the variables
a-2=0
We move all terms containing a to the left, all other terms to the right
a=2
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