(3x+10)=(7x-38)

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Solution for (3x+10)=(7x-38) equation: 



(3x+10)=(7x-38)

We move all terms to the left:

(3x+10)-((7x-38))=0

We get rid of parentheses

3x-((7x-38))+10=0



We calculate terms in parentheses: -((7x-38)), so:

(7x-38)

We get rid of parentheses

7x-38

Back to the equation:

-(7x-38)



We get rid of parentheses

3x-7x+38+10=0

We add all the numbers together, and all the variables

-4x+48=0

We move all terms containing x to the left, all other terms to the right

-4x=-48

x=-48/-4

x=+12

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