3(3n+1)-5(n-1)=2(n+3)+2(n+1)

Solution for 3(3n+1)-5(n-1)=2(n+3)+2(n+1) equation:

3(3n+1)-5(n-1)=2(n+3)+2(n+1)

We move all terms to the left:

3(3n+1)-5(n-1)-(2(n+3)+2(n+1))=0

We multiply parentheses

9n-5n-(2(n+3)+2(n+1))+3+5=0


We calculate terms in parentheses: -(2(n+3)+2(n+1)), so:

2(n+3)+2(n+1)

We multiply parentheses

2n+2n+6+2

We add all the numbers together, and all the variables

4n+8

Back to the equation:

-(4n+8)


We add all the numbers together, and all the variables

4n-(4n+8)+8=0

We get rid of parentheses

4n-4n-8+8=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0