3(8+c)=2(c-1)

Solution for 3(8+c)=2(c-1) equation:

3(8+c)=2(c-1)

We move all terms to the left:

3(8+c)-(2(c-1))=0

We add all the numbers together, and all the variables

3(c+8)-(2(c-1))=0

We multiply parentheses

3c-(2(c-1))+24=0


We calculate terms in parentheses: -(2(c-1)), so:

2(c-1)

We multiply parentheses

2c-2

Back to the equation:

-(2c-2)


We get rid of parentheses

3c-2c+2+24=0

We add all the numbers together, and all the variables

c+26=0

We move all terms containing c to the left, all other terms to the right

c=-26