(6X+10)(6x-10)=15+(3x-5)(12x-5)

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Solution for (6X+10)(6x-10)=15+(3x-5)(12x-5) equation: 



(6X+10)(6X-10)=15+(3X-5)(12X-5)

We move all terms to the left:

(6X+10)(6X-10)-(15+(3X-5)(12X-5))=0

We use the square of the difference formula

36X^2-(15+(3X-5)(12X-5))-100=0

We multiply parentheses ..

36X^2-(15+(+36X^2-15X-60X+25))-100=0



We calculate terms in parentheses: -(15+(+36X^2-15X-60X+25)), so:

15+(+36X^2-15X-60X+25)

determiningTheFunctionDomain
(+36X^2-15X-60X+25)+15

We get rid of parentheses

36X^2-15X-60X+25+15

We add all the numbers together, and all the variables

36X^2-75X+40

Back to the equation:

-(36X^2-75X+40)



We get rid of parentheses

36X^2-36X^2+75X-40-100=0

We add all the numbers together, and all the variables

75X-140=0

We move all terms containing X to the left, all other terms to the right

75X=140

X=140/75

X=1+13/15

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