4(2x-3)+12=3(x-3)-(2x+1)

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Solution for 4(2x-3)+12=3(x-3)-(2x+1) equation: 



4(2x-3)+12=3(x-3)-(2x+1)

We move all terms to the left:

4(2x-3)+12-(3(x-3)-(2x+1))=0

We multiply parentheses

8x-(3(x-3)-(2x+1))-12+12=0



We calculate terms in parentheses: -(3(x-3)-(2x+1)), so:

3(x-3)-(2x+1)

We multiply parentheses

3x-(2x+1)-9

We get rid of parentheses

3x-2x-1-9

We add all the numbers together, and all the variables

x-10

Back to the equation:

-(x-10)



We add all the numbers together, and all the variables

8x-(x-10)=0

We get rid of parentheses

8x-x+10=0

We add all the numbers together, and all the variables

7x+10=0

We move all terms containing x to the left, all other terms to the right

7x=-10

x=-10/7

x=-1+3/7

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