3(7-4x)=8(x-1)-5x+11

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Solution for 3(7-4x)=8(x-1)-5x+11 equation: 



3(7-4x)=8(x-1)-5x+11

We move all terms to the left:

3(7-4x)-(8(x-1)-5x+11)=0

We add all the numbers together, and all the variables

3(-4x+7)-(8(x-1)-5x+11)=0

We multiply parentheses

-12x-(8(x-1)-5x+11)+21=0



We calculate terms in parentheses: -(8(x-1)-5x+11), so:

8(x-1)-5x+11

We add all the numbers together, and all the variables

-5x+8(x-1)+11

We multiply parentheses

-5x+8x-8+11

We add all the numbers together, and all the variables

3x+3

Back to the equation:

-(3x+3)



We get rid of parentheses

-12x-3x-3+21=0

We add all the numbers together, and all the variables

-15x+18=0

We move all terms containing x to the left, all other terms to the right

-15x=-18

x=-18/-15

x=1+1/5

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