6(1-2x)=4-(4x+3)

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Solution for 6(1-2x)=4-(4x+3) equation:



6(1-2x)=4-(4x+3)
We move all terms to the left:
6(1-2x)-(4-(4x+3))=0
We add all the numbers together, and all the variables
6(-2x+1)-(4-(4x+3))=0
We multiply parentheses
-12x-(4-(4x+3))+6=0
We calculate terms in parentheses: -(4-(4x+3)), so:
4-(4x+3)
determiningTheFunctionDomain -(4x+3)+4
We get rid of parentheses
-4x-3+4
We add all the numbers together, and all the variables
-4x+1
Back to the equation:
-(-4x+1)
We get rid of parentheses
-12x+4x-1+6=0
We add all the numbers together, and all the variables
-8x+5=0
We move all terms containing x to the left, all other terms to the right
-8x=-5
x=-5/-8
x=5/8

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