3(6+7y)+3(1-5y)=42

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Solution for 3(6+7y)+3(1-5y)=42 equation:



3(6+7y)+3(1-5y)=42
We move all terms to the left:
3(6+7y)+3(1-5y)-(42)=0
We add all the numbers together, and all the variables
3(7y+6)+3(-5y+1)-42=0
We multiply parentheses
21y-15y+18+3-42=0
We add all the numbers together, and all the variables
6y-21=0
We move all terms containing y to the left, all other terms to the right
6y=21
y=21/6
y=3+1/2

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